in arithmetic sequence 11th term is 41 and 14th term is 46.find 8th term
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Answer:The distance between 11 and 14 is 3, as well as the 8 to 11. 46 (14th term) subtracted by 41 (11st term) is 5. Therefore, 41 subtracted by 5 is 36 which is the 8th term.
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