In arrangement shown the normal reaction betweenbthe block A and groung
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20N
Explanation:
In the given arrangement we may conclude that A and B will not show any motion now thus we may say that they are in equilibrium.
Now the normal due to 4 kg block in the system will be given by mg i.e (black marker)
assumed that g=10m/s^2
mass so T(4) = 40N
similarly T(2) = 20N
Here tensions and normal are same as string is perpendicular and tension is also perpendicular so pulley have two tensions (orange marker)
so both of tensions will result in an overall tension of 20N as
40-20= 20N
Now as A is heavy so the tension work by his side (green marker)
and normal is equal to tension so
Normal at A = 20 N
Normal at B= -20 N
Figures are not good but its 2AM bro
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