Question

In arrhenius equation for a certain reaction ,the values of A and Ea are 4×10^13 sec^-1 and 98.6KJmol^-1 respectively .The specific rate constant is 1.1 ×10^-3 S^-1 then temperature is

Answer 1

Arrhenius equation is-

K=Ae^(-Ea/RT)
Putting the value of A , K , Ea , R we can calculate value of T
The temperature is 311 K

Answer 2

The temperature is 311 K

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

where,

$K$ = specific rate constant

$Ea$ = activation energy with catalyst

A= pre exponential factor

R = gas constant = 8.314 J/Kmol

T = temperature = ?

Now put all the given values in this formula, we get

$1.1\times 10^{-3}=4\times 10^{13}s^{-1}\times e^{\frac{-98.6\times 10^3}{8.314 J/Kmol\times T}}$

$ln(0.275\times 10^-{16}={\frac{-98.6\times 10^3J/mol}{8.314 J/Kmol\times T}}$

$-38.1={\frac{-98.6\times 10^3J/mol}{8.314 J/Kmol\times T}}$

$T=311K$

Thus the temperature is 311 K

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