in Ashok room there are two fans of 75w each two tubes of 40 w each and a bulb of 5 w if all the appliances are used for six hours calculate how much units of electricity is consumed
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Answered by
19
I unit of electric current = 1000 WH or 1000 KWH
Total power consumed = (75+75+40+40+5)W ×6H
= 235 W × 6 H
= 1310 WH = 1.310 KWH
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Answered by
19
Answer:1.41 kWh
Explanation:
Total energy by fans = .15 kW
Total energy by tubes = .08 kW
Total energy by bulb = .005 kW
Total time = 6 h
Total electricity = 6(.15+.08+.005)
Total electricity = 6(.235)
Total electricity = 1.41 kWh
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