Question

in asset of integers,the average of the two smallest integers is 102,the average of the three smallest integers is 103,the average of the all four is 104,which is the greatest of these integers​

Answer 1

Answer:

Let the integers be a,b,c,d

such that a<b<c<d

2

a+b

=102⇒a+b=204

3

a+b+c

=103⇒a+b+c=309

4

a+b+c+d

=104⇒a+b+c+d=416

⇒d=416−309=107