Computer Science, asked by sikandarsayyed69, 2 months ago

In astable multivibrator, if RA= 1 KO RB= 5 KO and C= 0.1 uF, TON is?​

Answers

Answered by kelangovan2310
0

Answer:

a++++++ss hole bi. tc. h. =

Answered by sanket2612
0

Answer:

The answer is 410 us.

Explanation:

In a stable multi vibrator, the high state time period T_{HIGH} is also known as T_{ON}.

It is basically the time period for which the output is high.

T_{ON} is calculated as:

T_{ON} = 0.693(R_{A} + R_{B}) C

      = 0.693 x (1 + 5) x 0.1 x 10^{-3}

       = 410 us

Hence, the answer is 410 us.

#SPJ3

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