Question

In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 × 10^(–18) J from the radiations of 600 nm, calculate the number of photons received by the detector.

Answer 1

Answer:

400 of the answer for you by tomorrow morning if you want to give it is a not so sure

Answer 2

$\rule{200}3$

$\Huge{\purple{\underline{\textsf{Answer}}}}$

$\sf Energy\: of\: photon,\:\: E = \dfrac{hc}{\lambda}$

$\textbf{Given\::}$ $\sf Wavelength\:(\lambda) = 600nm = 600 \times 10^{8}$

$\sf Energy\: of\:1\: photon,\: E = \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^{8}}{600 \times 10^{-9}}$

$\pink\longrightarrow$ $\pink{\sf 3.313 \times 10^{-9}J}$

$\rule{200}3$

$\sf Number\: of \: photons = \dfrac{Total\:energy\: received}{Energy\: of \: 1 photon}$

$:\red\implies$ $\sf \dfrac{3.15\times 10^{-18}}{3.313 \times 10^{-19}}$

$:\red\implies$ $\underline{\boxed{\red{\sf 0.9507 \times 10^{1}\:photon}}}$ $\orange\bigstar$

$\rule{200}3$