Question

In athletic competition, the record jump in the pole vault was 6
3
4 Meters. An athlete set a
new record jump of 8
1
2
meters. What percentage of the old record is the difference between
the two records? Correct your answer to 2 decimal places.

Answer 1

$Given \:old \: record \:jump \: in \: pole$

$vault = 6.34 \:m$

$New \: record = 8.12 \:m$

$Difference \: between \:two \: records$

$(d) = 8.12 \:m - 6.34 \: m$

$= 1.78 \: m$

$Percentage \: of \: difference$

$= \frac{d}{Old \: record } \times 100$

$= \frac{1.78}{6.34} \times 100$

$= 28.07 \%$

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Answer 2

$\bf{\underline{\underline{\bigstar\bigstar\: Given : }}}$

$\:$

• $\footnotesize{ Old \: record = 6.34 \: meters }$

• $\footnotesize{ New \: record = 8.12 \: meters }$

$\:$

$\bf{\underline{\underline{\bigstar\bigstar\: To \: Find : }}}$

$\:$

• $\footnotesize{ percentage \: of \: difference \: between \: two \: record }$

$\:$

$\bf{\underline{\underline{\bigstar\bigstar\: Solution :}}}$

$\:$

$\footnotesize{ Difference \: between \: two \: record = 8.12 - 6.34 \: meters }$

$\footnotesize{\implies Difference \: between \: two \: record = 1.78\: meters }$

$\:$

$\rule{200}3$

$\:$

$\footnotesize{\implies Difference \: percentage = \dfrac{ Difference}{Old \: record} \times 100\% }$

$\footnotesize{\implies Difference \: percentage = \dfrac{ 1.78 meters}{6.34 \: meters} \times 100\% }$

$\footnotesize{\implies Difference \: percentage = 0.2807 \times 100\% }$

$\footnotesize{\implies Difference \: percentage = 28.07\% }$

$\:$

$\footnotesize{\bold{ Difference \: percentage = 28.07\% }}$

$\:$

$\bold{\underline{\underline{\bigstar \: Learn \: more, : }}}$

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