Question

In athletic competition, the record jump in the pole vault was 17/2 Meters. An athlete set a new record jump of 27/4
meters. What percentage of the old record is the difference between
the two records? Correct your answer to 2 decimal places.

Answer 1

Answer:

the percentage between the 2 records are 66percent

Answer 2

$Old \: record = \frac{17}{2} \: m$

$New \: record = \frac{27}{4} \:m$

$\red{Difference\: between\:the \:two \: records(d)} \\= \frac{17}{2} - \frac{27}{4} \\= \frac{34-27}{4} \\= \frac{7}{4} \:m\\\green {= 1.75 \:m }$

$\red{Percentage \: of \: record} = \frac{d}{new \: record } \times 100 \\= \frac{\frac{7}{4}}{\frac{27}{4}} \times 100 \\= \frac{700}{27} \\\green {= 25.92\%}$

•••♪