Question

In atom with l=2 and m=2, what is the angle between the angular momentum vector and the z axis?

Answer 1

Answer:

  0.582

Explanation:

Given Data:

l=2

m=2

Find Out:

cos θ=   m/ $\sqrt[]{l(l+1)}$

Solution:

cos θ=  2/$\sqrt[]{2(2+1)}$

cos θ=  2/2.4     =0.83

θ= $cos^{-1}$ 0.83

θ=0.582