in atraingle if sin3B/sinB=(a2-c2/2ac,then a2,b2
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(
sinB
3sinB−4sin
3
B
)=(
2ac
a
2
−C
2
)
2
3−4sin
2
B=(
2ac
a
2
−C
2
)
2
(4cos
2
B−1)=(
2ac
a
2
−C
2
)
2
4cos
2
B=(
2ac
a
2
+C
2
)
2
2cosB=
2ac
a
2
+c
2
2
2ac
a
2
+c
2
−b
2
=
2ac
a
2
+C
2
2b
2
=a
2
+c
2
∴a
2
,b
2
,c
2
areinAP.
error
error
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