Question

IN ATRIANGLE, TWO ANGLES ARE OF THE SAME MEASURE AND THIRD ANGLE IS 30 DEGREE MORE THAN ONE EQUAL ANGLES. FIND THE MEASURE OF EACH ANGLE

Answer 1

Answer:

50,50,80

Step-by-step explanation:

Sum of all the interior angles of a triangle is 180°.

let  ∠A = ∠B

and

∠C = 30 + ∠A

Let ∠A = x

Hence ∠A + ∠B + ∠C = x + x + 30 + x = 3x + 30

3x + 30 = 180

⇒ 3x = 150

⇒ x = 50

Hence ∠A = ∠B = 50 and ∠C = 80

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GeniusH