Question

In attachment given solve

Answer 1

Question :

Six particles situated at the corners of a regular hexagon of side a move at a constant speed v. Each  particle maintains a  direction towards the particle at the next corner. Calculate the time the particles will take to meet each other .

Answer:

$\large \dfrac{2a}{v}$

Explanation:

Given :

Side of regular hexagon = a

velocity = v

We have to find time ( t )

The total displacement of one particle with respect to other = a

So relative velocity ( V r ) = v - v cos 60

We know value of cos 60 = 1 / 2

$\large V_r=v-v/2=v/2$

We know formula for relative velocity

$\large \text{Relative velocity = \dfrac{Total \ displacement}{Total \ time} }$

Put the value here we get

$\large \dfrac{v}{2} =\dfrac{a}{t}\\\\\\\large t=\dfrac{2a}{v}$

Thus we get answer.

Answer 2

V2a......... Thanks......... Thanks