In auxiliary memory address space is of 12 bits and memory space of 7 bits. The page consists of 64 words. How many pages are required in the system ?
128
64
32
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Number of words in the address space is 2^{24} [/tex]
Number of words in the memory space is 2^{16} [/tex]
Number of pages = / 2k = 16 M/2k = 8k pages
Number of blocks = / 2k = 64k/2k = 32 blocks
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