Question

in balanced reaction
$H_2SO_4 + xHI = H_2S +yI2+zH2O$
The value of x y and z is

Answer 1

x= 8 y= 4 and z= 4. Hope you are satisfied with the answer.

Answer 2

Explanation:

Correct option is

C

x=8,y=4,z=4

To balance the number of iodine atoms, HI is multiplied with 2.

Iodine is oxidized. Its oxidation state changes from −1 to 0. Net increase is +2.

Sulphur is reduced. Its oxidation state changes from 6 to −2. Net decrease is 8.

To balance the net increase and net decrease in the oxidation number, factor 4 is used. Thus, coefficients of HI and I

2

are multiplied by 4.

To balance oxygen atoms, four water molecules are required on the right.

Thus, x=8, y=4 and z=4.