Question

In ballistics demonstration a police officer fires a bullet of 50g with a speed of 200 m/sec in the soft plywood of a thickness 2cm the bullet emerges with only 10% of its kinetic energy find the loss %in speed

Answer 1

Answer:

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Answer 2

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The initial kinetic energy of the bullet is ${mv}^2/2=1000J$

It has a final kinetic energy of${0.1×1000=100.J}$.

If ${vf}$ is the emergent speed of the bullet,

$\frac{1}{2}$ ${mv}^2$ ${f}$=${100J}$

${vf}$= $\sqrt{2×100J 0.05kg}$

=${63.2. m{s}^-1}$

☄.The speed is reduces by approximately 68% (not 90%).