Question

In bcc unit cell, edge length is 100 pm. What will be the radius
of atom?

(A) 433 pm
(B) 43.3 pm
(C) 230 pm
(D) 23 pm

​

Answer 1

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(B) 43.3 pm

Answer 2

The radius of the atom is 43.3 pm

Therefore, option (B) is correct.

Explanation:

Given:

Edge length in bcc unit cell d = 100 pm

To find out:

The radius of the atom

Solution:

We know that

In bcc unit cell the radius is given by

$r=\frac{\sqrt{3}d}{4}$   where d is edge length

Therefore,

$r=\frac{\sqrt{3}\times 100}{4}$

$\implies r=1.73\times 25$ pm

$\implies r=43.3$ pm

Hope this answer is helpful.

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