Question

In bcc unit cell, edge length is 100 pm. What will be the radius of atom?

(A) 433 pm (B) 43.3 pm (C) 230 pm (D) 23 pm​

Answer 1

Answer:

correct answer is

option b) 43.3 pm

Explanation:

as per formula for BCC

radius= √3/4 edge length

Answer 2

Answer:

Concept:

The radius of an atom is the length between the nucleus's centre and the outermost electrons. The size of the atoms of various elements, such as hydrogen, aluminium, and gold, varies with the size of the nucleus and the amount of energy held by the electrons. You may examine how an element's position in the periodic table affects the atom's size by looking at a chemical elements that lists atomic radius.

Given:

The edge length in a bcc unit cell is 100 pm. What will the atom's radius be?

(A) 433 pm

(B) 43.3 pm

(C) 230 pm

(D) 23 pm​

Find:

find What will be the radius of atom?

Answer:

Only by calculating the length between the nuclei of two contacting atoms and then reducing that distance can the radius of an atom be determined. As seen in the diagrams, the same atom may have a varied radius dependent on what was surrounding it.

The atom's radius is 43.3 pm.

The radius of a bcc unit cell is determined by

$r=\frac{\sqrt{3d} }{4}$

Therefore,

$r=\frac{\sqrt{3*4} }{100}$

$r = 1.73*25 pm\\r = 43.3 pm$

∴ the radius of atom is $43.3 pm$

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