In bcc unit cell ,edge length is 100pm what will be the radius of atom? a) 433pm b) 43.3 c) 230pm d) 23pm
Answers
Answered by
2
Answer:
b) 43.3
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Answered by
1
Answer:
b) 43.3 pm
Explanation:
for bcc:
a = 4r/√3
100√3/4 = r
r = 25√3
r = 25× 1.732
r= 43.3 pm
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