Chemistry, asked by mgadhvigadhvi, 9 months ago

In bcc unit cell ,edge length is 100pm what will be the radius of atom? a) 433pm b) 43.3 c) 230pm d) 23pm​

Answers

Answered by shanjusankar
2

Answer:

b) 43.3

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Answered by bhumikamangela040420
1

Answer:

b) 43.3 pm

Explanation:

for bcc:

a = 4r/√3

100√3/4 = r

r = 25√3

r = 25× 1.732

r= 43.3 pm

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