Question

In bcc unit cell, Edge length is 100pm. what will be the radius of atom?

Answer 1

Answer:

radius = 43.25 pm.

Explanation:

Let edge length , a = 100 pm.

     radius  , r = ?

For a BCC unit cell,  $4r =\sqrt{3}a$

                          =>   $4r = \sqrt{3} (100)$

                          =>    $4r = 173$

                          =>   r =43.25 pm.

Answer 2

Answer is 43.25 pm


43.25