Math, asked by loveablekya, 1 year ago

In △BCD, d = 3, b = 5, and m∠D = 25°. What are the possible approximate measures of angle B?

Answers

Answered by Rockyhandsome2345
0
65 degree will be the answer
we know that 3,4,5 is Pythagoras triplet
then BCD is right angle triangle
then , 90+25+angle b= 180°
angle b = 65°
Answered by vaduz
0

Answer: 90°


Step-by-step explanation:

as given two sides are 3 cm and 5 cm. so thisrd side must be 4 cm because

we know that 3,4,5 is Pythagoras triplet

then BCD is a right angle triangle at B because b(CD) is given 5 cm which is hypotenuse of triangle. so ∠B= 90°

we know sum of all triangle's angle is 180°

so

∠B+∠C+∠D =180°

∠D+90°+25°=180°

∠D=65°

so triangle have sides 3, 4, 5 and angle 90°, 25°, 65°.

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