Math, asked by OtakuSama, 1 day ago

In ΔBDC, BD⊥DC, and E, is the midpoint of BC.

Prove that:- BD² + CD² = 2 (CE² + DE²)

◍ Good explanation needed!! No spamming please!!

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Answered by anjudad1

1

Answer:

take two ️ ️BED AND DEC

by RHS property solve it

angle BED ~ angle DEC =90°

DE is common

Answered by karubhaisurela10

10

Step-by-step explanation:

I try my best to explain this.

hope this helps you...☺️

HAPPY LEARNING ✨

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