in be drawn on a
igure.
ΟΥ
m
6 cm
(c) 20 + 12 - E= 2
or 32 - E= 2
E=32 - 2 = 30
Thus, the number of edges = 30.
Example 2. Can a polyhedron have 10 faces, 20
edges and 15 vertices?
Solution. The given data will be of a polyhedron, if it
satisfies the Euler's formula
i.e., V + F-E = 2.
Here,
V = 15, F = 10 and E = 20
Putting these values in L.H.S.
15 + 10 - 20 = 5 * R.H.S.
L.H.S. R.H.S
rmula find the
(c)
Answers
Answered by
0
Answer:
it 193.340*
Step-by-step explanation:
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