Question

In below attachment ,lines xy and MN intersect at O. If angle poy =90° and a:b= 2:3.find c ????

Answer 1

$\bf\huge \gray{ANSWER}$

$\large\text \blue{GIVEN THAT:}$

$\sf{ = > Angle \: POY= 90°}$

$\large\text \pink{WE KNOW THAT:}$

• The sum of linear pair angles or angles on line is 180 °

$\sf{ = > Angle \: POY +a+b =180°}$

$\sf{ = > a + b = 180 - 90}$

$\sf{ = > a + b = 90°}$

$\large\text \blue{GIVEN THAT:}$

$\sf{ = > a :b = 2:3}$

$\large\text\red{ASSUME THAT }$

• Let a be 2x and b be 3x

$\sf{ = > 2x + 3x = 90°}$

$\sf{ = > 5x = 90°}$

$\sf = > {x = \frac{90°}{5} }$

$\bf{ = > x = 18}°$

$\large\text\purple{Therefore }$

$\bf{a = 2 \times 18 = 36°}$

$\bf{b = 3 \times 18 = 54°}$

$\large\text\orange{Here }$

• Angel MON is 180°
• MN is straight line
• In above diagram b+ c also form straight line

$\large\text\purple{Therefore }$

$\sf {= > b + c = 180° }$

$\sf{ = > c + 54 = 180°}$

$\large \boxed {c = 126°}$

Answer 2

Step-by-step explanation:

GIVEN THAT:

\sf{ = > Angle \: POY= 90°}=>AnglePOY=90°

\large\text \pink{WE KNOW THAT:}WE KNOW THAT:

The sum of linear pair angles or angles on line is 180 °

\sf{ = > Angle \: POY +a+b =180°}=>AnglePOY+a+b=180°

\sf{ = > a + b = 180 - 90}=>a+b=180−90

\sf{ = > a + b = 90°}=>a+b=90°

\large\text \blue{GIVEN THAT:}GIVEN THAT:

\begin{gathered} \sf{ = > a :b = 2:3} \\ \end{gathered}

=>a:b=2:3

\large\text\red{ASSUME THAT }