in below figure we have AD=1/2 AB AND BE=1/2 BC. IF AB=BC show that AD=CE
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Given :
AB = BC
AD = 1/2 AB
BE = 1/2 BC
To prove : AD = CE
CE = BC - BE
But it is given BE = 1/2 BC
= > CE = BC - 1/2 BC
= > CE = BC - BC / 2
= > CE = ( 2 BC - BC ) / 2
= > CE = BC / 2
But BC = AB [ Given ]
So :
CE = AB / 2
Also AD = AB / 2
So :
CE = AD [ Proved ]
Anonymous:
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