Question

in between two consecutive squares numbers n square and (n+1)whole square there exists non perfect square number(2n .3n, 2n+1​

Answer 1

Step-by-step explanation:

Both n^2 and (n+1)^2 are perfect square numbers and they are consecutive perfect squares.

⇒ All the numbers between them are non-perfect square.

Numbers between n^2 and (n+1)^2 are

=(n+1)2−n^2−1

=n^2+2n+1−n^2−1

=2n

⇒ There are 2n non-perfect square numbers.