Question

in binomial distribution n=18 and p-q =1/3 then what is the value of standard deviation​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Concept Introduction: Binomial distribution is the advanced concepts of Mathematics.

Given:

We have been Given:

$n = 18 \\ p - q = \frac{1}{3}$

To Find:

We have to Find: The Value of Standard Deviation.

Solution:

According to the problem, we know,

$p + q = 1$

and here given to us is

$p - q = \frac{1}{3} \\ p = \frac{1}{3} + q$

now putting the value of p in first equation, we get,

$( \frac{1}{3} + q) + q = 1 \\ \frac{1 + 6q}{3} = 1 \\ 6q + 1 = 3 \\ 6q = 2 \\q = \frac{2}{6} = \frac{1}{3}$

therefore now finding variance,

$variance = npq \\ variance = 18 \times \frac{1}{3} \times \frac{1}{3} \\ variance = 2$

therefore, the standard deviation is

$std. \: deviation = \sqrt{variance} \\std. \: deviation = \sqrt{2} = 1.414$

Final Answer: The Standard Deviation is

$1.414$

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