In binomial distribution n=6 and p=0.9, then the value of p(x=7) is
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In a binomial distribution b(n, p), the probability of r successes out of n trials is given by ; P(X = r) = C(n, r).p^(r)q^(n-r) ; r = 0, 1, 2, …. .. (n-1).
By definition, n = 6 means you have 6 trials .
You cannot have 7 occurrences in 6 binomial trials.
So the P( X = 7) = 0
Additionally, the formula is not defined for X >6.
P(X=k) = (n k) (p)^k (1-p)^(n-k)
Means
X has values 0,1,2,3,4,5, and 6
X cannot be bigger than N
X will never be 7
P(X = 7) = 0
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