Question

in bissextile year have 53 sanday so say probability

Answer 1

A leap year has 366 days. Now 364 is divisible by 7 and therefore there will be two excess week days in a leap year. The two excess week days can be (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday). So, the sample space S has 7 pairs of excess week days. i.e. n(S) = 7.

Now we want the desired event E to have 53 Sundays and 53 Mondays . E consists of only one pair in S which is (Sunday, Monday). So n(E) = 1

Hence, the probability that a leap year will contain 53 Sundays and 53 Mondays = n(E)/n(S) = 1/7