● In bode plot, the phase angle for the factor 1/(1+jw/5) will be? Answer A. O tan-1 (w/5) B. O tan-1 (5/w) D. O-tan-1 (5/w) C.O-tan-1 (w/5) Support Numbi
Answers
Answer:
Mean of the data is 18.33.
Step-by-step explanation:
We are given the following data below ;
2/3, 5/3, 1/3, 5/6, 1/6
Now, as we know that formula for finding mean for any discrete data is given by;
Mean, \bar XXˉ = \frac{\sum X}{n}n∑X
where, \sum X∑X = Sum of all the observations in data
n = number of observations
Here, the obs. are : \frac{2}{3} ,\frac{5}{3} ,\frac{1}{3} ,\frac{5}{6} ,\frac{1}{6}32,35,31,65,61
Firstly, we will try to make the denominator same for all the given fraction values, that is;
\frac{2}{3} = \frac{2 \times 2}{3 \times 2} =\frac{4}{6}32=3×22×2=64
\frac{5}{3} = \frac{5 \times 2}{3 \times 2} =\frac{10}{6}35=3×25×2=610
\frac{1}{3} = \frac{1 \times 2}{3 \times 2} =\frac{2}{6}31=3×21×2=62
\frac{5}{6} = \frac{5 \times 1}{6 \times 1} =\frac{5}{6}65=6×15×1=65
\frac{1}{6} = \frac{1 \times 1}{6 \times 1} =\frac{1}{6}61=6×11×1=61
Now, Mean of the data, \bar XXˉ = \frac{\frac{4}{6}+\frac{10}{6}+\frac{2}{6}+\frac{5}{6}+\frac{1}{6} }{5}564+610+62+65+61
= \frac{22}{6}\times 5622×5 = 18.33
Hence, the mean of the given data is 18.33.