CBSE BOARD XII, asked by ramh, 7 months ago

In Bohr model of hydrogen atom, the electron moves around the
nucleus in a circular orbit of radius of 0.53 A° at a frequency of 6.8
X10* MHz. Calculate magnetic induction at the centre of the orbit.
What is the equivalent dipole moment?

Answers

Answered by msjayasuriya4
0

Answer:

In Bohr's model of hydrogen atom, the electron circulates round the nucleus in a path of radius 5×10

−11

m at a frequency of 6.8×10

15

revolutions per second. The value of magnetic induction at the centre of the orbit is :

MEDIUM

Share

Study later

ANSWER

∣B∣ =

2r

μ

0

i

I=

dt

dq

= qf

= 1.6×10

−19

×6.8×10

15

=10.88×10

−4

∴∣B∣=

2×5×10

−11

4π×10

−7

×10.88×10

−4

=13.6T

Answered By

toppr

How satisfied are you with the answer?

This will help us to improve better

answr

Get Instant Solutions, 24x7

No Signup required

girl

More Questions by difficulty

EASY

MEDIUM

HARD

Similar questions