Question

In Bohr‘s hydrogen atom, the electronic transition emitting light of longest wavelength is:

Answer 1

Explanation:

from n = 1 to n = 2 because energy is lowest due to the formula lambda = hc / Energy

Answer 2

Answer:

n=4 to n=3

Explanation:

We know that ΔE=Rh[(1/n1^2)-(1/n2^2)]

Thus the decreasing order of energy transition is :

n=2 to n=3 > n=2 to n=1 > n=3 to n=2 > n=4 to n=3

Also, E= hc/λ

Thus that should be the increasing order of wavelength.

Thus the transition of the longest wavelength is n=4 to n=3