Question

In Bohr's model of hydrogen atom, the total energy of the electron in
nth discrete orbit is proportional to
(A) n
(B)1
(C)n^2
(D)1/n^2​

Answer 1

Answer:

c) n^2

Explanation:

I hope it will be help you

Answer 2

Given:

Bohr's model of hydrogen atom.

To find :

Dependency of energy on number of orbital.

Solution :

According to Bohr's model of hydrogen atom

electrons revolve around positive charge in circular orbit.

Total energy of nth orbital =

$\bf \frac{2\pi ^{2}m {e}^{4}Z^2 }{n^2h^2(4\pi \epsilon _ 0) ^{2} } = - 13.6 \frac{Z^2}{n^2} \:$

where m = mass of electron.

e = charge of electron.

Z = Atomic number.

n = number kf orbital.

h = plank's constant.

Putting all the values of m,e,n and h in above equation and

For hydrogen atom

Z = 1

So, Energy of nth orbital of hydrogen atom =

$\bf \: \frac{ - 13.6}{ {n}^{2} } eV \:$

$\textbf{\Large Energy of nth orbital} \propto \bf \: \frac{1}{n^2} \:$

So, Option D is correct.