Math, asked by vikasbathwalvb, 23 days ago

In both Algebraic Identities and Equations, L.H.S = R.H.S, then why do identities satisfy every value of the variable, whereas equations don't? Equation: 2x - 3 = 5x + 12 Identity: a² - b² = (a - b)(a + b)

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Answered by derick247

Answer:

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Step-by-step explanation:

It is equality of identity of both sides after solving as for as in trigonometry etc is concerned. Or in other cases we take an equation to equal to zero for finding solutions etc. LHS i.e. meaning expression on the left side of the sign = and RHS meaning the expression on the right side of the sign =.

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In both Algebraic Identities and Equations, L.H.S = R.H.S, then why do identities satisfy every value of the variable, whereas equations don't? Equation: 2x - 3 = 5x + 12 Identity: a² - b² = (a - b)(a + b)​

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In both Algebraic Identities and Equations, L.H.S = R.H.S, then why do identities satisfy every value of the variable, whereas equations don't? Equation: 2x - 3 = 5x + 12 Identity: a² - b² = (a - b)(a + b)