In brief state what happens when: (a) dry apricots are left for some time in pure water? (b) a red blood cell is kept in concentrated saline solution? (c) the plasma membrane of a cell breaks down?
Answers
Explanation:
Due to the movement of water outside the cell, it shrinks up. Thus, when dry apricots are left for some time in pure water then they swell due to endosmosis, and later when they are transferred to the sugar solution, they shrink due to exosmosis.
Answer:
a) When a dry apricot is placed inside pure water for some time, it will swell up as water enters inside the apricot. It occurs due to endosmosis. Here the concentration of solute is lower in water than inside the apricot. Thus water enters inside to maintain equilibrium.
After that if the swollen apricot is placed inside sugar solution it will shrink again due to exosmosis. As the sugar solution has higher solute concentration the liquid inside the apricot comes out towards the solution with higher concentration resulting in shrinkage of the fruit.
b) If a red blood cell is placed inside concentration saline solution, the water will come out and the cell will shrink. This happens because the concentration of the solution outside is higher than inside the cell. Thus as a result of osmosis, water comes out of the cell to maintain equilibrium.
c)The water from the high concentration (surrounding) will enter the cell. [The cell will swell]
d.The cell will remain unaffected.
e.Salt draws out the bitter juice from bitter gourd and makes it dehydrate and less bitter
Explanation: