Question

In Cannizzaro reaction given $2PhCHO \xrightarrow[]{: \overset{\ominus}{O}H} PhCH_2OH + PhC \ddot{O}_2^{\ominus}$ the slowest step is :
(a) the transfer of hydride to the carbonyl group
(b) the abstraction of proton from the carboxylic group
(c) the deprotonation of Ph CH₂OH
(d) the attack of $: \overset{\ominus}{O}H$ at the carboxyl group

Answer 1

Here is your answer ⤵⤵⤵

a) the transfer of hydride to the carbonyl group

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Answer 2

$<b>$
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→ [B]

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