Question

In carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of agbr. The percentage of bromine in the compound is: (at. Mass ag =108; br = 80) (a) 48

Answer 1

Answer:24

Explanation:

Answer 2

Answer:

Given :

$\small\tt\red{organic compound =250mg}$

$\small\tt\pink{weight of compound =141mg}$

$\small\tt\orange{Ag=108 ,br=80}$

$\small\tt\red{total atomic=188}$

Explanation:

Percentage of bromine::

$\\ \red\bigstar\tt\: \dfrac{80x250x100}{188x141}$

$\\ \red\bigstar\tt\: \dfrac{40x250x100}{94x141}$

By solving this get

$\huge\boxed{\fcolorbox{red}{blue}{</p><p>Answer=24}}$