Question

in carnot heat engine,
is work done from A to B = RT1 log V2/V1 ?
or nRT1 log V2/V1



please answer



physics question.​

Answer 1

In case of one mole of an ideal gas, the work done during isothermal process is,

$W=RT_1\log\left (\dfrac {V_2}{V_1}\right)$

In case of n moles of the gas, the work done is,

$W=nRT_1\log\left (\dfrac {V_2}{V_1}\right)$

Usually first case, i.e., one mole of gas is considered.