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Steam at 100 °C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15 °C till the temperature
of the calorimeter and its contents rises to 80 °C. The mass of the steam condensed in kg is (Given specific heat capacity of
water = 1 kcal kg-1 °C-1, latent heat of condensation of steam = 540 kcal kg-1)
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Explanation:
Steam at 100^@C is passed into 1.1 kg of water contained in a ... 0.02 kg at 15^@Ctill the temperature of the calorimeter
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Answer:
The mass of the steam condensed in kg is 0.130 kg.
Explanation:
Given,
Steam at 100ºC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15ºC till the temperature of the calorimeter and its contents rises to 80ºC.
To find: The mass of the steam condensed in kg.
Solution:
Applying conservation of heat Energy,
Heat released by steam = heat gained by water and calorimeter
mL + m × S (100 – 80) = (1.1 + 0.02) × S × (80 – 15)
m × 540 + 20 m = 1.12 × 65
m = 0.130 kg.
Therefore, The mass of the steam condensed in kg is 0.130 kg.
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