Question

in case if the angle of a prism is 60 degree and the angle of minimum deviation is 37.2 degree the refractive index of the prism will be ...,...!

Answer 1

Explanation:

If the angle of prism is 60 degree and the angle of minimum deviation is 37.2 degree the refractive index of the prism will be?

Answer 2

Answer:

Refractive index of prism with prism angle 60° is 1.5

Explanation:

Angle of deviation in a prism is  the  shift in angle if incident light beam on the prism . The relation between angle of prism, angle of deviation and refractive index of prism is given by following relation.

         $\mu = \frac{sin (\frac{\alpha+ A}{2}) }{sin( \frac{A}{2} )} \\\\\mu = refractive\ \ index \ \ of \ \ prism \\ \alpha = angle\ \ of \ \ deviation\\A= angle \ \ of \ \ prism$

Given : A= 60°  α=37.2°

so,

  $\mu = \frac{sin(\frac{37.2+ 60}{2} )}{sin(\frac{60}{2} )} \\\\\mu = \frac{sin(48.6)}{sin(30)} \\\\\mu = \frac{0.75}{0.5} \\\\\mu = 1.5$

Hence refractive index of prism is 1.5