Question

In case of a frequency distribution for ten continuous classes, the class width is 4 and the lower class limit of
the lowest class is 8. What is the upper class limit for the highest class?
S only
Neither R nor S
R only
Both R&S
​

Answer 1

Answer:

Class interval=(high−low value +1)

=8−1+1

=8.

Step-by-step explanation:

Answer 2

Answer:

48

Step-by-step explanation:

if x and y are upper and lower class limits

then x-y = 4 ; y = 8

now, x= 12 means upper limit of lower class

now for upper limit for the highest class = no.of continuous class * class width + lower class limit

I.e = 10*4 + 8 = 48