In case of ch3cooh the oxidation number of carbon of carboxylic group is
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CH3COOH
4+1×3+C+(-2)+(-2)+1=0
4+C=0
C=-4
Oxidation no of C is minus 4
4+1×3+C+(-2)+(-2)+1=0
4+C=0
C=-4
Oxidation no of C is minus 4
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In , the oxidation number of carbon of carboxylic group is -3.
Explanation:
- In the given compound there are 2 carbons. One carbon is attached with three hydrogen atoms, whereas the other carbon is attached with 2 oxygen atoms and one hydrogen atom.
- As per the general rule, hydrogen acquires +1 charge when it is attached with a non-metal, whereas oxygen acquires -2 charge when it is attached with a non-metal.
- The structure of the carboxylic group given in the attachment is observed, it shows that the 2 oxygen atoms are attached to the carbon (non-metal) and one hydrogen atom is attached to oxygen (non-metal) atom.
- When calculation is done as per the structure it gives:
COOH
Let the oxidation number of carbon in carboxylic acid be "X"
X = (-2)+(-2)+1
X = (-4) + 1
X = -3
∴ From the above calculation it is inferred that the oxidation number of carbon of the carboxylic group is -3.
Learn more about oxidation number
Calculate the oxidation oxidation number of underlined atoms.
1. H2so4
2. HNO3
3. H3PO3
4. K2C2O4
5. H2S4O6
6. Cr2O7
7. NaH2pO7
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The oxidation number of arsenic atom in H3AsO4 is :
(A) –5
(B) +1
(C) –3
(D) +5
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