in case of combination if C0+C1+C2+........ +Cn=256, then 2nC2 is equal to?
Answers
Answer:
Heya buddy....
Here is ur answer....
120 is the answer.....
Step-by-step explanation:
If set S has n elements, then C( n,k) is the number of ways of choosing k elements from S
Thus the number of subsets of S of all possible is given by
C( n,0) + C ( n,1) + C(n,3) +......
Comparing the given equation :
2^n = 256
2^n = 2^8
n = 8
Thus
2n C2 = 16 C2
= (16 × 15) /2
=120
Hope it’s helpful......... ☺
Answer:
Heya buddy....
Here is ur answer....
120 is the answer.....
Step-by-step explanation:
If set S has n elements, then C( n,k) is the number of ways of choosing k elements from S
Thus the number of subsets of S of all possible is given by
C( n,0) + C ( n,1) + C(n,3) +......
Comparing the given equation :
2^n = 256
2^n = 2^8
n = 8
Thus
2n C2 = 16 C2
= (16 × 15) /2
=120
Hope it’s helpful......... ☺
Answer:
Heya buddy....
Here is ur answer....
120 is the answer.....
Step-by-step explanation:
If set S has n elements, then C( n,k) is the number of ways of choosing k elements from S
Thus the number of subsets of S of all possible is given by
C( n,0) + C ( n,1) + C(n,3) +......
Comparing the given equation :
2^n = 256
2^n = 2^8
n = 8
Thus
2n C2 = 16 C2
= (16 × 15) /2
=120
Hope it’s helpful......... ☺
Answer:
Heya buddy....
Here is ur answer....
120 is the answer.....
Step-by-step explanation:
If set S has n elements, then C( n,k) is the number of ways of choosing k elements from S
Thus the number of subsets of S of all possible is given by
C( n,0) + C ( n,1) + C(n,3) +......
Comparing the given equation :
2^n = 256
2^n = 2^8
n = 8
Thus
2n C2 = 16 C2
= (16 × 15) /2
=120