Question

In case of parallel plate capacitor, if the plate separation is doubled and plate area is halved, the capacitance become

Answer 1

Answer:

capacitance becomes one fourth of original

Answer 2

$\huge \bold \color{lime} \star{ \underline{ \color{teal} \underline \mathfrak{Answer }}} \star$

$c = \frac{ \epsilon_{0} \: A}{d}$

$c' = \frac{ \epsilon_{0}2A }{ \frac{d}{2} }$

$c' = \frac{ \epsilon_{0}4 A }{d}$

$\huge \color{lime} \boxed{ \color{green} \boxed {\therefore \: c' = 4c}}$

Hope it helps