Question

In case of pure inductance connected across AC supply
Options
O Current and Voltage are out of phase
Current and Voltage are in phase
Current lead the voltage by 90 degrees
O Current lags the voltage by 90 degrees
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Clear Response​

Answer 1

Answer:

In the purely inductive circuit above, the inductor is connected directly across the AC supply voltage. As the supply voltage increases and decreases with the frequency, the self-induced back emf also increases and decreases in the coil with respect to this change.

Answer 2

Given : pure inductance connected across AC supply

To Find : Choose correct option :

Current and Voltage are out of phase

Current lead the voltage by 90 degrees

Current lags the voltage by 90 degrees

Current and Voltage are in phase​

Solution:

in case of  Pure inductive circuit:  Inductor current lags inductor voltage by 90°

Current lags the voltage by 90°

For Resistive circuit  Current and voltage are in phase

in case of pure capacitance  Current lead the voltage by 90°

in case of Resistance + capacitance and or  inductance

Current and Voltage are out of phase

Current lags the voltage by 90°  is correct option

in case of pure inductance connected across AC supply

inductive circuits

Positive phase for inductive circuits

current lags the voltage in pure inductive circuit by  π/2  

Capacitive circuits

Negative phase for Capacitive circuits

current leads the voltage in pure Capacitive circuit by  π/2  

Hence Voltage lags the current  by  π/2  

Resistive circuits

Voltage ( EMF) & current are in same phase for pure resistive circuit

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