Question

in case of pure rolling what will be the velocity of point a of the ring of radius r

Answer 1

in case of rolling motion

velocity of any point on the ring is vector sum of transnational velocity and tangential velocity

So we can write like

$\vec v = \vec v_0 + R\vec \omega$

so here since its in pure rolling so at the bottom position

$\vec v = 0 = \vec v_0 - R\vec \omega$

so at any other position we can write

$\vec v = \vec v_0  + \vec v_0$

if angle between them is "theta"

$v = \sqrt{v_0^2 + v_0^2 + 2v_0^2 cos\theta}$

so above is the velocity of the object

Answer 2

Answer:Answer is in the attachment ..

It will help u ...

Explanation: