In cases of negative work the angle between the force and diapalcement is
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Hey friend here is ur solution..
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As work done is F.S = FScosA
(A=angle b/w f and s)
So it must be -ve when cos(A) is -ve
Which is -ve on every odd multiple of π i.e on
(2n+1)π
or A ©{π/2,3π/2}
___________________
Hope this will help you....
_________________
As work done is F.S = FScosA
(A=angle b/w f and s)
So it must be -ve when cos(A) is -ve
Which is -ve on every odd multiple of π i.e on
(2n+1)π
or A ©{π/2,3π/2}
___________________
Hope this will help you....
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