In CAT entrance examination paper there are 3 sections, each containing 5 questions. A candidate has to solve 5 questions, choosing at least one from each section. The number of ways he can choose is:
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1
He can choose...
1) 2 questions each from 1st & 2nd sets & 1 question from 3rd set...
2) 2 questions each from 1st & 3rd sets & 1 question from 2nd set...
3) 2 questions each from 2nd & 3rd sets & 1 question from 1st set...
Hope my answer is complete... Plz mark as Brainliest if I helped U...
1) 2 questions each from 1st & 2nd sets & 1 question from 3rd set...
2) 2 questions each from 1st & 3rd sets & 1 question from 2nd set...
3) 2 questions each from 2nd & 3rd sets & 1 question from 1st set...
Hope my answer is complete... Plz mark as Brainliest if I helped U...
Anonymous:
He can also choose 3 questions from either one....and 1-1 from others......
Answered by
0
It is the question of COMBINATION..........= nCr = n!/r!(n-r)!
Here in your case, n=5 & r=3 so,
5C3 = 5!/3!(5-3)! = 5! /3! * 2!
You can write it as, =5 * 4 * 3 * 2 * 1 / 3 * 2 * 1 * 2 * 1
= 20/2 = 10.
So, the number of ways he can choose is 10.
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