Question

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.

Answer 1

Step-by-step explanation:

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Answer 2

Given :- In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot. ?

Solution :-

In right angled ∆DEC, we have,

→ DE = perpendicular .

→ EC = Base = x feet .

→ DC = Hypotenuse = 95 feet .

→ ∠DCE = 43° .

we know that,

• Cos θ = Base / Hypotenuse .

so,

→ cos 43° = EC / DC

→ cos 43° = x / 95

→ x = cos 43° * 95

→ x = 0.73 * 95

→ x = 69.35

→ x = 69.4 feet (Ans.)

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