Question

In CE configuration, if β = 100, leakage current ICEO = 150 μA. If the base current is 0.2 mA, calculate the value of IC, IE and α.​

Answer 1

Explanation:

beta = Ic / Ie

alpha = beta / (1 - beta)

Ie = Ic + Ib

1. alpha = 100 /99

2. alpha = Ic / Ib

Ic = alpha x Ib

= 100/99 x 0.2 x 10 ^-3

3. Ie = Ic + Ib = Ic/ beta = 1/ 99 x 0.2 x.10^-3A

Answer 2

Answer:

Collector current, $I_{C}=20mA$, Emitter current, $I_{E}=20.2mA$,  Common base current amplification, $\alpha = 0.99$

Explanation:

Given in CE configuration,

                     current gain, $\beta = 100$

         leakage current $I_{CEO} = 150 \mu A$

                  base current, $I_{B} = 0.2 mA$

Current gain, $\beta =\frac{I_{C} }{I_{B}}\implies I_{C}=\beta \times I_{B}$

Therefore, collector current, $I_{C}=100 \times 0.2=20mA$

Emitter current, $I_{E}=I_{B}+I_{C}$

                            $=0.2+20=20.2mA$

Common base current amplification,

                      $\alpha = \frac{I_{C} }{I_{E}}$

                          $= \frac{20 }{20.2}=0.99$